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For proper design of a shaft, it should be designed on the basis of

AMaximum principal stress theory

BMaximum shear stress theory

CBoth 1 and 2

DMaximum strain theory

Answer:

B. Maximum shear stress theory

Read Explanation:

Shaft should be designed based on the maximum shear stress theory. According to this theory, failure occurs when the maximum shearing stress reaches the failure value equal to that developed at yielding in an axial tensile or compressive test of the same material. This theory is well justified for ductile materials. The equation for design is $\sigma_{1} - \sigma_{2}\le (\sigma_{Y} / FOS)$ where $\sigma_{1}$ and $\sigma_{2}$ are maximum and minimum principal stress respectively, and $\sigma_{y}$ is the permissible stress


Related Questions:

The maximum shear stress theory predicts that the yield strength in shear is the yield strength in tension.
From Rankine's hypothesis Rankine, criteria for failure of brittle material is:
Design of shafts made of brittle material is based on

Consider the following statements :Which of the statements is/are correct?

  1. Based on the experiment results, the distortion energy theory predicts the failure of a component made of ductile material most accurately.
  2. According to the distortion energy theory, the shear yield strength is less than the shear strength in tension.
    According to Tresca's maximum shear stress criterion, plastic deformation occurs when maximum shear stress is equal to K, where K is equal to:(where σ₁, σ₂, σ₃ are principal stresses and also σ₁ ≥ σ₂ ≥ σ₃)