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1427+131113+159=\frac{1}{4\frac{2}{7}}+\frac{1}{3\frac{11}{13}}+\frac{1}{\frac{5}{9}}=

A312/45

B513/13

C218/35

D172/75

Answer:

D. 172/75

Read Explanation:

Step 1: Convert the mixed fractions to improper fractions

  • For the first term: 427=(4×7)+27=3074\frac{2}{7} = \frac{(4 \times 7) + 2}{7} = \frac{30}{7}

  • For the second term: 31113=(3×13)+1113=50133\frac{11}{13} = \frac{(3 \times 13) + 11}{13} = \frac{50}{13}


Step 2: Reciprocate the fractions

Since each term is under a 1x\frac{1}{x} format, we invert the fractions:

  • 1307=730\frac{1}{\frac{30}{7}} = \frac{7}{30}

  • 15013=1350\frac{1}{\frac{50}{13}} = \frac{13}{50}

  • 159=95\frac{1}{\frac{5}{9}} = \frac{9}{5}

Now substitute these back into the original expression:
730+1350+95\frac{7}{30} + \frac{13}{50} + \frac{9}{5}


Step 3: Find the Common Denominator

The Least Common Multiple (LCM) of the denominators 3030, 5050, and 55 is 150150.

Convert each fraction to have a denominator of 150150:

  • 7×530×5=35150\frac{7 \times 5}{30 \times 5} = \frac{35}{150}

  • 13×350×3=39150\frac{13 \times 3}{50 \times 3} = \frac{39}{150}

  • 9×305×30=270150\frac{9 \times 30}{5 \times 30} = \frac{270}{150}


Step 4: Add the numerators together

35+39+270150\frac{35 + 39 + 270}{150}
=344150= \frac{344}{150}


Step 5: Check and re-verify calculations

Let's double-check the calculations carefully.

  • First term: 1/(30/7)=7/301 / (30/7) = 7/30

  • Second term: 1/(50/13)=13/501 / (50/13) = 13/50

  • Third term: 1/(5/9)=9/51 / (5/9) = 9/5

  • Sum: 35150+39150+270150=344150\frac{35}{150} + \frac{39}{150} + \frac{270}{150} = \frac{344}{150}

  • Simplifying 344150\frac{344}{150} by dividing numerator and denominator by 2 gives 17275\frac{172}{75}.


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