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(1232)1/2(78+3)1/4243(1/5)\frac{(123-2)^{1/2}(78+3)^{1/4}}{243^{(1/5)}}

A10

B11

C12

D13

Answer:

B. 11

Read Explanation:

(1232)1/2(78+3)1/4243(1/5)\frac{(123-2)^{1/2}(78+3)^{1/4}}{243^{(1/5)}}

=(121)1/2(81)1/4243(1/5)=\frac{(121)^{1/2}(81)^{1/4}}{243^{(1/5)}}

=11×(34)(1/4)(35)(1/5)=\frac{11 \times (3^4)^{(1/4)}}{(3^5)^{(1/5)}}

=11×33=\frac{11 \times 3}{3}

=11=11


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