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(110÷16100)of3.20.4+120÷4of3×10(\frac1{10}\div\frac{16}{100})\text{of} \frac{3.2}{0.4}+120\div4 \text{of} 3\times10

A100

B110

C105

D90

Answer:

C. 105

Read Explanation:

(110÷16100)of3.20.4+120÷4of3×10(\frac1{10}\div\frac{16}{100})\text{of} \frac{3.2}{0.4}+120\div4 \text{of} 3\times10

=1016×8+120÷12×10=\frac{10}{16}\times8+120\div12\times10

=5+10×10=5+10\times10

=105=105


Related Questions:

Which of the following interchanges of signs would make the given equation correct ?

5×4÷108+2=85\times4\div10-8+2=8

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Find the value of

[(63÷9)×[968+114×(95)]][(63\div9)\times[\frac{96}{8}+\frac{11}{4}\times(9-5)]]

125.99 - 35.92 + 3.89 × 16.11 = ?

154+8×3+5:15 - 4 + 8 \times 3 + 5: