$\frac{(123-2)^{1/2}(78+3)^{1/4}}{243^{(1/5)}}$

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A10

B11

C12

D13

Answer:

$\frac{(123-2)^{1/2}(78+3)^{1/4}}{243^{(1/5)}}$

$=\frac{(121)^{1/2}(81)^{1/4}}{243^{(1/5)}}$

$=\frac{11 \times (3^4)^{(1/4)}}{(3^5)^{(1/5)}}$

$=\frac{11 \times 3}{3}$

$=11$

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