Question

$\frac{2^3\times4^6\times8^2}{16^4}=2^x$find x

• A. 7
• B. 4
• C. 5
• D. 8

Answer 1

Answer:

C. 5

$\frac{2^3\times4^6\times8^2}{16^4}=2^x$

$\frac{2^3\times(2^2)^6\times(2^3)^2}{(2^4)^4}=2^x$

$\frac{2^3\times2^{12}\times2^6}{2^{16}}=2^x$

$\frac{2^{21}}{2^{16}}=2^x$

$2^{21-16}=2^x$

$2^5=2^x$

$x=5$