$\frac{(7^6)^2}{7^7}=?$

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A $7^5$

B $7^12$

C $7^6$

D $7^19$

Answer:

7^5

$\frac{(7^6)^2}{7^7}=\frac{7^{6\times2}}{7^7}$

$=7^{12-7}=7^5$

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