Question

$\frac{\sqrt{25}+_3\sqrt{216}}{\sqrt{121}}=?$

• A. 11
• B. 0
• C. 1
• D. 3

Answer 1

Answer:

C. 1

$\frac{{\sqrt25}+_3\sqrt{216}}{\sqrt121}=?$

$\frac{5+6}{11}=11/11$

$=1$