Question

$f(x)=\frac{x}{x-1}$ ആയാൽ $\frac{f(a)}{f(a+1)}=$

• A. $$f(a^2)$$
• B. $$\frac{-a}{a-1}$$
• C. $$f(\frac{1}{a})$$
• D. f(-a)

Answer 1

Answer:

$$f(a^2)$$

$f(a)= \frac{a}{a-1}$

$f(a+1) = \frac{a+1}{a}$

$\frac{f(a)}{f(a+1)}c= \frac{\frac{a}{a-1}}{\frac{a+1}{a}} = \frac{a^2}{(a+1)(a-1)}=\frac{a^2}{a^2-1}$

$=f(a^2)$