Question

$$HCF OF $\frac23,\frac45,\frac67$

• A. $$\frac{2}{105}$$
• B. $$\frac{3}{110}$$
• C. $$\frac{1}{105}$$
• D. $$\frac{1}{110}$$

Answer 1

Answer:

$$\frac{2}{105}$$

$$ HCF of fractions= $\frac{HCF of numerators}{LCM of Denominators}$

$=\frac{HCF (2,4,6)}{LCM(3,5,7)}=\frac{2}{3\times5\times7}$

$=\frac{2}{105}$.