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How many diagonals can be drawn in a pentagon?

A6

B7

C5

D8

Answer:

C. 5

Read Explanation:

Solution: Concept used : Number of diagonals in polygon = [n(n - 3)]/2 (where n is the number of sides) Calculations : Here n will be 5 as pentagon has 5 sides. Number of polygons in octagon = [5 × (5 - 3)]/2 ⇒ (2 × 5)/2 ⇒ 5 ∴ The answer is 5.


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