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If 1 is added to each odd digit and 1 is subtracted from each even digit in the number 7873262, what will be the sum of the digits that are third and fourth from the left in the new number thus formed?

A12

B18

C10

D16

Answer:

A. 12

Read Explanation:

The sum of the digits that are third and fourth from the left in the new number is 12.

  1. Identify the original digits:
    The given number is 7873262.

  2. Apply the operations:

    • 7 (odd) →7+1=\rightarrow 7 + 1 = 8

    • 8 (even) →8−1=\rightarrow 8 - 1 = 7

    • 7 (odd) →7+1=\rightarrow 7 + 1 = 8

    • 3 (odd) →3+1=\rightarrow 3 + 1 = 4

    • 2 (even) →2−1=\rightarrow 2 - 1 = 1

    • 6 (even) →6−1=\rightarrow 6 - 1 = 5

    • 2 (even) →2−1=\rightarrow 2 - 1 = 1

  3. Form the new number:
    The newly formed number is 8784151.

  4. Calculate the final sum:

    • The third digit from the left is 8.

    • The fourth digit from the left is 4.

    • Sum = 8+4=8 + 4 = 12.


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