Question

if 16+11=A and 1/g=B, and A % B=(A×B)-1, then what is A % B?

• A. 0
• B. -3
• C. 2
• D. 5

Answer 1

Answer:

C. 2

First find the values of A and B:

A = 16 + 11 = 27
$B = \frac{1}{9}$

Given:
$A \% B = (A \times B) - 1$

Substitute the values:

$(27\times\frac{1}{9})-1=3-1=2$

Therefore, A % B = 2.