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if 16+11=A and 1/g=B, and A % B=(A×B)-1, then what is A % B?

A0

B-3

C2

D5

Answer:

C. 2

Read Explanation:

First find the values of A and B:

A = 16 + 11 = 27
B=19B = \frac{1}{9}

Given:
A%B=(A×B)−1A \% B = (A \times B) - 1

Substitute the values:

(27×19)−1=3−1=2(27\times\frac{1}{9})-1=3-1=2

Therefore, A % B = 2.

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