If 20 # 4 = -5, 50 # 25 = -2 and 80 # 16 = -5, then find the value of 10 # 2 = ?A-30B-40C-20D-5Answer: D. -5 Read Explanation: The Logic followed here is:-(First number ÷ Second number)×(−1)=Result\times{(-1)}= Result×(−1)=ResultIn 20 # 4 = -5(20÷4)×(−1)=−5(20\div{4})\times{(-1)} = -5(20÷4)×(−1)=−5In 50 # 25(50÷25)×(−1)=−2(50\div{25})\times{(-1)} = -2(50÷25)×(−1)=−2In 80 # 16(80÷16)×(−1)=−5(80\div{16})\times{(-1)} = -5(80÷16)×(−1)=−5Similarly,In 10 # 2(10÷2)×(−1)=−5(10\div{2})\times{(-1)} = -5(10÷2)×(−1)=−5Hence, the correct answer is "-5". Read more in App