If 2^m = 16, what is 3^(m -1)?

Challenger App

★

1M+ Downloads

$2^m = 16$ ആയാൽ $3^{(m -1)}$ എത്ര ?

A81

B27

D15

Answer:

2^4 = 16 , m =4 3^(4 -1) = 3 ^3 = 27

Related Questions:

(-1)^5 + (-1)^10 – (-1)^20 / 1^0 ?

$3^0 + 3^1 + 3^ 2 + 3^3 + 3^ 4 = x ^ 2$ എങ്കിൽ x ൻ്റെ വില എത്ര ?

$27^{1/3}\times8^{1/3}\times16^{1/4}=?$

$(-1)^{100} + (-1)^{101} =?$