If 3^10 × 27^2=9^2 × 3^n, find the value of n.

Challenger App

★

1M+ Downloads

3^10 × 27^2=9^2 × 3^n ആയാൽ. n ന്റെ വില കണ്ടെത്തുക

A12

B15

C30

D10

Answer:

3^10 × 27^2=9^2 × 3^n 3^10 × (3³)² = (3²)² × 3^n 3^10 × 3^6 = 3^4 × 3^n 3^(10+6) = 3^(4+n) 16 = 4 +n n = 12

Related Questions:

(2^0 + 2^-1) × 2^2 = ?

$x^y = y^x$ കൂടാതെ x = 2y എങ്കിൽ y എത്ര ?

$(x/y)^{12}.y^{24}.(z^3)^4=$