If 4^n = 1024, what is 4^(n-2)?

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$4^n = 1024$ ആയാൽ $4^{(n-2 )}$ എത്ര ?

B16

C64

D256

Answer:

$4^n = 1024$

$4^5 = 1024$

$n = 5$

$4^(n-2) = 4^3 = 64$

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