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If 5 # 3 = 19 and 7 # 2 = 17, what is 9 # 1?

A12

B10

C8

D11

Answer:

D. 11

Read Explanation:

A simpler pattern fits the given examples:

  • (5#3=5×3+4=19)(5 \# 3 = 5 \times 3 + 4 = 19)

  • (7#2=7×2+3=17)(7 \# 2 = 7 \times 2 + 3 = 17)

The added number decreases by 1 each time:

  • (+4, +3,) so next is (+2)

Therefore,

9#1=9×1+2=119 \# 1 = 9 \times 1 + 2 = 11

So the answer is 11.


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