634+X=1114+214 6 \frac {3}{4} + X = 11 \frac {1}{4} + 2 \frac {1}{4}643+X=1141+241 എങ്കിൽ x എത്ര ? A$6 \frac {3}{4}$B$6 \frac {1}{2}$C$6 \frac {1}{4}$D$6 \frac {2}{3}$Answer: $6 \frac {3}{4}$ Read Explanation: 634+X=1114+2146\frac34+X=11\frac14+2\frac14643+X=1141+241 X=1114+214−634X = 11\frac14+2\frac14-6\frac34X=1141+241−643 X=45/4+9/4−27/4X=45/4 + 9/4 - 27/4X=45/4+9/4−27/4X=(45+9−27)/4X=(45+9-27)/4X=(45+9−27)/4X=(54−27)/4X=(54-27)/4X=(54−27)/4=27/4=634=27/4=6\frac34=27/4=643 Read more in App
