If 60% of A = 0.3 of B = 1/6 of C, find A: B: C.A5:10:18B18:10:5C6:3:10D10:5:18Answer: A. 5:10:18 Read Explanation: Given:60% of A=0.3 of B=16 of C60\% \text{ of } A = 0.3 \text{ of } B = \frac{1}{6} \text{ of } C60% of A=0.3 of B=61 of CConvert to fractions:35A=310B=16C\frac{3}{5}A = \frac{3}{10}B = \frac{1}{6}C53A=103B=61CLet the common value be (k).Then:35A=k⇒A=5k3\frac{3}{5}A = k \Rightarrow A=\frac{5k}{3}53A=k⇒A=35k310B=k⇒B=10k3\frac{3}{10}B = k \Rightarrow B=\frac{10k}{3}103B=k⇒B=310k16C=k⇒C=6k\frac{1}{6}C = k \Rightarrow C=6k61C=k⇒C=6kSo,A:B:C=5k3:10k3:6kA:B:C = \frac{5k}{3} : \frac{10k}{3} : 6kA:B:C=35k:310k:6kMultiply by 3 to remove denominators:5k:10k:18k5k : 10k : 18k5k:10k:18kTherefore,5:10:18\boxed{5:10:18}5:10:18 Read more in App