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A=÷A = \div, B=+B = +, C=−C = -, D=×D = \times ആയാൽ 15 D 2 B 14 A 7 C 1015\text{ D } 2\text{ B } 14\text{ A } 7\text{ C } 10 എത്ര?

A20

B21

C22

D24

Answer:

C. 22

Read Explanation:

BODMAS നിയമപ്രകാരം അക്ഷരങ്ങൾക്ക് പകരം ചിഹ്നങ്ങൾ മാറ്റി എഴുതുക:
15×2+14÷7−1015 \times 2 + 14 \div 7 - 10

  1. ഹരണം : 14÷7=214 \div 7 = 2
    →15×2+2−10\rightarrow 15 \times 2 + 2 - 10

  2. ഗുണനം : 15×2=3015 \times 2 = 30
    →30+2−10\rightarrow 30 + 2 - 10

  3. കൂട്ടൽ : 30+2=3230 + 2 = 32
    →32−10\rightarrow 32 - 10

  4. കുറയ്ക്കൽ : 32−10=2232 - 10 = \mathbf{22}

  • ശരിയായ ഉത്തരം: 22


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