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If A is a n-square matrix, then.

A∣adjA∣=∣A∣(n−1)|adj A|= |A| ^ {(n - 1)}

B∣adjA∣=∣A∣n |adj A|= |A|^n

C∣adjA∣=∣A∣|adj A|= |A|

D∣adjA∣=∣A∣(n+1)|adj A|= |A|^{(n + 1)}

Answer:

∣adjA∣=∣A∣(n−1)|adj A|= |A| ^ {(n - 1)}

Read Explanation:

∣adjA∣=∣A∣(n−1)|adj A|= |A| ^ {(n - 1)}


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