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If at same rate of interest, in 2 years, the simple interest is ₹40 and compound interest is ₹65, then what is the principal (in ₹)?

A11

B16

C20

D9

Answer:

B. 16

Read Explanation:

For 2 years:

Simple Interest (SI)

SI=P×r×2100=40\text{SI} = \frac{P \times r \times 2}{100} = 40

⇒Pr=2000(1)\Rightarrow Pr = 2000 \quad (1)

Difference between CI and SI (for 2 years)

CI−SI=65−40=25\text{CI} - \text{SI} = 65 - 40 = 25

For 2 years:
CI−SI=Pr210000\text{CI} - \text{SI} = \frac{P r^2}{10000}

⇒Pr210000=25\Rightarrow \frac{P r^2}{10000} = 25

⇒Pr2=250000(2)\Rightarrow Pr^2 = 250000 \quad (2)

Divide (2) by (1)

Pr2Pr=2500002000\frac{Pr^2}{Pr} = \frac{250000}{2000}

⇒r=125\Rightarrow r = 125

Find Principal

From (1):
P×125=2000P \times 125 = 2000
⇒P=16\Rightarrow P = 16

Final Answer:

Principal = ₹16


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