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If at same rate of interest, in 2 years, the simple interest is ₹40 and compound interest is 856, then what is the principal (in ₹)?

A25

B18

C29

D20

Answer:

A. 25

Read Explanation:

Let principal be (P) and rate be (r%) per annum.

Use Simple Interest (2 years)

SI=P⋅r⋅2100=40SI = \frac{P \cdot r \cdot 2}{100} = 40
⇒Pr=2000(1)\Rightarrow Pr = 2000 \quad (1)

Use Compound Interest (2 years)

For 2 years,
CI−SI=Pr21002CI - SI = \frac{P r^2}{100^2}

Given CI is intended as ₹56 (since ₹856 is inconsistent with SI = 40 and standard 2-year CI problems).

So,
CI−SI=56−40=16CI - SI = 56 - 40 = 16
⇒Pr210000=16\Rightarrow \frac{P r^2}{10000} = 16

Pr2=160000(2)Pr^2 = 160000 \quad (2)

Solve

From (1), (Pr = 2000)

Divide (2) by (1):
Pr2Pr=1600002000\frac{Pr^2}{Pr} = \frac{160000}{2000}
r = 80

Find (P)

P=200080=25P = \frac{2000}{80} = 25

Final Answer:

₹25\boxed{₹25}


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