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If at same rate of interest, in 2 years, the simple interest is ₹44 and compound interest is ₹45, then what is the principal (in ₹)?

A488

B477

C484

D479

Answer:

C. 484

Read Explanation:

Let principal = P, rate = R%

Simple Interest (2 years)

SI=PR×2100=44SI = \frac{PR \times 2}{100} = 44

PR100=22...(1)\frac{PR}{100} = 22 \quad ...(1)

Compound Interest (2 years)

CI=P(1+R100)2−P=45CI = P\left(1 + \frac{R}{100}\right)^2 - P = 45

For 2 years:
CI=SI+PR21002CI = SI + \frac{P R^2}{100^2}

So,
45=44+PR21000045 = 44 + \frac{P R^2}{10000}

PR210000=1\frac{P R^2}{10000} = 1

PR2=10000...(2)P R^2 = 10000 \quad ...(2)

Use (1)

From (1):

PR = 2200

Square it:
P2R2=22002P^2 R^2 = 2200^2

P2R2=4,840,000P^2 R^2 = 4,840,000
Divide with (2)

PR2=10000PR^2 = 10000

Divide:
P2R2PR2=484000010000\frac{P^2 R^2}{PR^2} = \frac{4840000}{10000}
P = 484

Final Answer: ₹484


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