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If at same rate of interest, in 2 years, the simple interest is ₹44 and compound interest is ₹46, then what is the principal (in ₹)?

A237

B235

C246

D242

Answer:

D. 242

Read Explanation:

Let principal = (P), rate = (r%) per annum, time = 2 years.

Simple Interest (SI)

SI=Pr2100=44SI = \frac{P \cdot r \cdot 2}{100} = 44
Pr100=22(1)\Rightarrow \frac{Pr}{100} = 22 \quad \text{(1)}

Difference between CI and SI

For 2 years:
CISI=P(r100)2CI - SI = P\left(\frac{r}{100}\right)^2

Given:
4644=246 - 44 = 2
P(r100)2=2(2)\Rightarrow P\left(\frac{r}{100}\right)^2 = 2 \quad \text{(2)}

Solve using (1) and (2)

From (1):
r100=22P\frac{r}{100} = \frac{22}{P}

Substitute into (2):
P(22P)2=2P \left(\frac{22}{P}\right)^2 = 2
P484P2=2P \cdot \frac{484}{P^2} = 2
484P=2\frac{484}{P} = 2

P = 242
Principal = ₹242


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