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If cos (θ + 31°) = sin 47°, then what is the value of sin 5θ?

A½

B1/√2

C√3/2

D0

Answer:

C. √3/2

Read Explanation:

cos (θ + 31°) = sin 47° cos (θ + 31°) = sin (90 - 43)° cos (θ + 31°) = cos 43° θ = 12° Sin 5θ = sin 60° = √3/2

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The value of cosec230∘sin⁡245∘+sec⁡260∘tan60∘cosec245∘−sec⁡260∘tan45∘\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}  is: