If xy=32\frac{x}{y}=\frac{3}{2}yx=23 ,then find x2+y2x2−y2\frac{x^2+y^2}{x^2-y^2}x2−y2x2+y2 A$\frac{13}{5}$B$\frac{11}{5}$C$\frac{7}{5}$D$\frac{9}{5}$Answer: $\frac{13}{5}$ Read Explanation: Given, xy=32\frac{x}{y}=\frac{3}{2}yx=23Hence, x2+y2x2−y2=32+2232−22\frac{x^2+y^2}{x^2-y^2}=\frac{3^2+2^2}{3^2-2^2}x2−y2x2+y2=32−2232+22=9+49−4=135=\frac{9+4}{9-4}=\frac{13}{5}=9−49+4=513 Read more in App
