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If xy=32\frac{x}{y}=\frac{3}{2} ,then find x2+y2x2y2\frac{x^2+y^2}{x^2-y^2}

A$\frac{13}{5}$

B$\frac{11}{5}$

C$\frac{7}{5}$

D$\frac{9}{5}$

Answer:

$\frac{13}{5}$

Read Explanation:

Given, xy=32\frac{x}{y}=\frac{3}{2}

Hence, x2+y2x2y2=32+223222\frac{x^2+y^2}{x^2-y^2}=\frac{3^2+2^2}{3^2-2^2}

=9+494=135=\frac{9+4}{9-4}=\frac{13}{5}


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