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If '+' means '−', '−' means '÷', '×' means '+', and '÷' means '×', what will be the value of the following expression?

[{(6×9)+(3÷2)}−(7+4)]÷2[\{(6 \times 9) + (3 \div 2)\} - (7 + 4)] \div 2

A4

B6

C8

D2

Answer:

B. 6

Read Explanation:

The correct value of the expression is 4.

  1. Substitute the signs according to the given rules:

    • Change + to −

    • Change − to ÷

    • Change × to +

    • Change ÷ to ×

    The original expression:
    [{(6×9)+(3÷2)}−(7+4)]÷2[\{(6 \times 9) + (3 \div 2)\} - (7 + 4)] \div 2 The newly substituted expression becomes:
    [{(6+9)−(3×2)}÷(7−4)]×2[\{(6 + 9) - (3 \times 2)\} \div (7 - 4)] \times 2

  2. Solve using the BODMAS rule (from the inside out):

    • Innermost Parentheses ( ):

      • (6+9)=15(6 + 9) = 15

      • (3×2)=6(3 \times 2) = 6

      • (7−4)=3(7 - 4) = 3

      The expression updates to: [{15−6}÷3]×2[\{15 - 6\} \div 3] \times 2

    • Curly Braces { }:

      • {15−6}=9\{15 - 6\} = 9

      The expression updates to: [9÷3]×2[9 \div 3] \times 2

    • Square Brackets [ ]:

      • [9÷3]=3[9 \div 3] = 3

    • Final Multiplication:

      • 3×2=63 \times 2 = 6


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36 - 2 × 8 ÷ 4 =

Find the value of

[(48÷8)×[497+404×(7−3)]][(48 \div 8)\times[\frac{49}{7}+\frac{40}{4}\times(7-3)]]