Question

If one diagonal of a rhombus of side 13 cm is 10 cm, then the other diagonal is

• A. 24 cm
• B. 20 cm
• C. 16 cm
• D. 28 cm

Answer 1

Answer:

A. 24 cm

AC = 10 cm.

AO = OC = 5 cm.

$\angle$ AOB = 90°

AB = 13 cm.

From $\triangle$ AOB,

$OB =\sqrt{AB^2-OA^2}=\sqrt{13^2-5^2}$

$=\sqrt{169-25}=\sqrt{144}$

$=12cm$

$BD=2OB=2\times{12}=24cm$