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If P is the circum-center in ΔABC, ∠BPC = 30°, then what is the value (in degrees) of ∠BAC?

A15

B60

C75

D105

Answer:

A. 15

Read Explanation:

∠BAC = 1/2 ∠BPC ∴ ∠BAC = 1/2 ⨯ 30° = 15°


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