Question

If p:q=4:1, find (5p+3q):(5p-3q).

• A. 23 : 17
• B. 17 : 23
• C. 7 : 17
• D. 17 : 7

Answer 1

Answer:

A. 23 : 17

Given

$pq=41\frac{p}{q}= \frac{4}{1}qp=14$

Let $p=4kp=4kp=4k and q=kq=kq=k.$

Now,

$5p+3q=5(4k)+3(k)=20k+3k=23k5p+3q = 5(4k)+3(k)=20k+3k=23k5p+3q=5(4k)+3(k)=20k+3k=23k$

and

$5p−3q=5(4k)−3(k)=20k−3k=17k5p-3q = 5(4k)-3(k)=20k-3k=17k5p−3q=5(4k)−3(k)=20k−3k=17k$

Therefore,

$(5p+3q):(5p−3q)=23k:17k=23:17(5p+3q):(5p-3q)=23k:17k=23:17(5p+3q):(5p−3q)=23k:17k=23:17$

Answer: 23 : 17