Question

If R019 is divisible by 11, find the value of the smallest natural number R.

• A. 5
• B. 6
• C. 7
• D. 8

Answer 1

Answer:

D. 8

Sum of the digit in odd places = 9 + 0 = 9 Sum of the digit in even places = R + 1 ∴ The difference of sum of odd place digit and sum of even place digit = (9 - R - 1) = 8 - R For a number to be divisible by 11 the difference has to be 0 or a multiple of 11 In this case, we get ⇒ 8 - R = 0 ⇒ R = 8