If sin2A−cos2A=14sin^2A-cos^2A=\frac{1}{4}sin2A−cos2A=41, find the value of cos2Acos^2Acos2A. A5/8B3/8C1/2D1/4Answer: B. 3/8 Read Explanation: Given:sin2A−cos2A=14\sin^2 A - \cos^2 A = \frac14sin2A−cos2A=41Use the identity:sin2A=1−cos2A\sin^2 A = 1 - \cos^2 Asin2A=1−cos2ASubstitute:(1−cos2A)−cos2A=14(1-\cos^2 A)-\cos^2 A=\frac14(1−cos2A)−cos2A=411−2cos2A=141-2\cos^2 A=\frac141−2cos2A=412cos2A=1−142\cos^2 A = 1-\frac142cos2A=1−412cos2A=342\cos^2 A = \frac342cos2A=43cos2A=34÷2\cos^2 A = \frac34 \div 2cos2A=43÷2cos2A=38\cos^2 A = \frac38cos2A=83So, the value is:38\boxed{\frac38}83 Read more in App