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If sin2A−cos2A=14sin^2A-cos^2A=\frac{1}{4}, find the value of cos2Acos^2A.

A5/8

B3/8

C1/2

D1/4

Answer:

B. 3/8

Read Explanation:

Given:

sin⁡2A−cos⁡2A=14\sin^2 A - \cos^2 A = \frac14

Use the identity:

sin⁡2A=1−cos⁡2A\sin^2 A = 1 - \cos^2 A

Substitute:

(1−cos⁡2A)−cos⁡2A=14(1-\cos^2 A)-\cos^2 A=\frac14
1−2cos⁡2A=141-2\cos^2 A=\frac14
2cos⁡2A=1−142\cos^2 A = 1-\frac14
2cos⁡2A=342\cos^2 A = \frac34
cos⁡2A=34÷2\cos^2 A = \frac34 \div 2
cos⁡2A=38\cos^2 A = \frac38

So, the value is:

38\boxed{\frac38}


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