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If the nth term of a GP is 128 and both the first term a and the common ratio r are 2. Find the number of terms in the GP.

A6

B8

C9

D7

Answer:

D. 7

Read Explanation:

a=2,r=2a=2,r=2

an=ar(n1)a_n=ar^{(n-1)}

128=2×2(n1)128=2\times2^{(n-1)}

27=2n2^7=2^n

n=7n=7


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