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If the simple interest on a certain sum for 18 months at 5.5% per annum exceeds the simple interest on the same sum for 14 months at 6% per annum by ₹62.50, then the sum is:

A₹7,000

B₹5,000

C₹6,500

D₹8,200

Answer:

B. ₹5,000

Read Explanation:

simple intrest SI=PNR100SI=\frac{PNR}{100}

SI1=P18125.5100SI_1=\frac{P\frac{18}{12}5.5}{100}

SI1=8.25P100SI_1=\frac{8.25P}{100}

SI2=P14126100SI_2=\frac{P\frac{14}{12}6}{100}

SI2=7P100SI_2=\frac{7P}{100}

SI1−SI2=8.25P100−7P100=62.50SI_1-SI_2=\frac{8.25P}{100}-\frac{7P}{100}=62.50

(8.25−7)P100=62.50\frac{(8.25-7)P}{100}=62.50

1.25P100=62.50\frac{1.25P}{100}=62.50

1.25P=62501.25P=6250

P=62501.25=5000P=\frac{6250}{1.25}=5000


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