If the sum of first and 50th term of an arithmetic sequence is 163 then the sum of first 50 terms of the sequence is :A8510B4075C4705D8150Answer: B. 4075 Read Explanation: a+a50=163a+a_{50}=163a+a50=163Sn=n2(a+an)S_n=\frac{n}{2}(a+a_n)Sn=2n(a+an)S50=502(a+a50)S_{50}=\frac{50}{2}(a+a_{50})S50=250(a+a50)=25×163=25\times 163=25×163=4075=4075=4075 Read more in App