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If the sum of first and 50th term of an arithmetic sequence is 163 then the sum of first 50 terms of the sequence is :

A8510

B4075

C4705

D8150

Answer:

B. 4075

Read Explanation:

a+a50=163a+a_{50}=163

Sn=n2(a+an)S_n=\frac{n}{2}(a+a_n)

S50=502(a+a50)S_{50}=\frac{50}{2}(a+a_{50})

=25×163=25\times 163

=4075=4075


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