If the tenth term of an AP is 20 and 20th term is 10, then the 30th term is :A0B10C20D30Answer: A. 0 Read Explanation: x10=20x_{10}=20x10=20x20=10x_{20}=10x20=10d=−1d=-1d=−1x30=x20+(30−20)dx_{30}=x_20+(30-20)dx30=x20+(30−20)dx30=10+(10)×−1x_{30}=10+(10)\times-1x30=10+(10)×−1x30=0x_{30}=0x30=0 Read more in App