Question

If the value of ΔG0 is -2502 J/mol and K is 2, what is the temperature of the reaction that is occurring?

• A. 200 k
• B. 101 k
• C. 100 k
• D. 300 k

Answer 1

Answer:

C. 100 k

We know that ΔG0 = – RT lnKc, where ΔG0 is the standard Gibbs free energy, R is universal gas constant, T is the temperature and KC is equilibrium constant; substituting ΔG0 as -2502 J/mol, we get -2502 J/mol = -8.314J mol^–1K^–1 × T ln2 = 2502 J/mol = T = 2502/2.502 = 100 k.