If x=3−2x = 3 - \sqrt{2}x=3−2 then find the value of 3x2+2x−43x^2+ 2x - 43x2+2x−4 A20−220-\sqrt{2}20−2B35+235+\sqrt{2}35+2C35−20235-20\sqrt{2}35−202D35−2235-2\sqrt{2}35−22Answer: 35−20235-20\sqrt{2}35−202 Read Explanation: 3x2+2x−43x ^ 2 + 2x - 43x2+2x−4 =3×(3−2)2+2(3−2)−4= 3 \times (3 - \sqrt{2}) ^ 2 + 2(3 - \sqrt{2}) - 4=3×(3−2)2+2(3−2)−4 =3(11−62)+6−22−4= 3(11 - 6\sqrt{2}) + 6 - 2\sqrt{2} - 4 =3(11−62)+6−22−4=35−202= 35 - 20\sqrt{2}=35−202 Read more in App
