If x=5+2x = \sqrt5 + 2x=5+2, find x2−45x^2-4\sqrt5x2−45. A1B7C9D3Answer: C. 9 Read Explanation: Given:x=5+2x=\sqrt5+2x=5+2Find:x2−45x^2-4\sqrt5x2−45First calculate (x^2):(5+2)2(\sqrt5+2)^2 (5+2)2=5+4+45=5+4+4\sqrt5=5+4+45=9+45=9+4\sqrt5=9+45Now,x2−45x^2-4\sqrt5x2−45=(9+45)−45=(9+4\sqrt5)-4\sqrt5=(9+45)−45=9=9=9So, the answer is:9\boxed{9}9 Read more in App