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If x=5+2x = \sqrt5 + 2, find x245x^2-4\sqrt5.

A1

B7

C9

D3

Answer:

C. 9

Read Explanation:

Given:

x=5+2x=\sqrt5+2

Find:

x245x^2-4\sqrt5

First calculate (x^2):

(5+2)2(\sqrt5+2)^2
=5+4+45=5+4+4\sqrt5
=9+45=9+4\sqrt5

Now,

x245x^2-4\sqrt5
=(9+45)45=(9+4\sqrt5)-4\sqrt5
=9=9

So, the answer is:

9\boxed{9}


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