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If  x⊕y=x2−y  \,\,x \oplus y = \frac{x}{2} - y\,\,and x∗y=y3−2x  \,x * y = \frac{y}{3} - 2x\,\,then find the value of (3⊕1)∗(4⊕−4)(3 \oplus 1) * (4 \oplus -4).

A-1

B0

C1

D2

Answer:

C. 1

Read Explanation:

The Combined Formula Method

We are given the two operations:

  1. x⊕y=x2−yx \oplus y = \frac{x}{2} - y

  2. A∗B=B3−2AA * B = \frac{B}{3} - 2A

We want to find the value of (3⊕1)∗(4⊕−4)(3 \oplus 1) * (4 \oplus -4).

Let's substitute the inner operations directly into the outer ∗* formula:

Value=(4⊕−4)3−2(3⊕1)\text{Value} = \frac{(4 \oplus -4)}{3} - 2(3 \oplus 1)

Now, substitute the definition of ⊕\oplus for both parts inside the structure:

Value=(42−(−4))3−2(32−1)\text{Value} = \frac{\left(\frac{4}{2} - (-4)\right)}{3} - 2\left(\frac{3}{2} - 1\right)

Now, simplify from left to right:

  1. Simplify the fractions inside the brackets:
    Value=(2+4)3−2(1.5−1)\text{Value} = \frac{(2 + 4)}{3} - 2\left(1.5 - 1\right)

  2. Solve the terms:
    Value=63−2(0.5)\text{Value} = \frac{6}{3} - 2(0.5)

  3. Final Calculation:
    Value=2−1=1\text{Value} = 2 - 1 = \mathbf{1}


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