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If θ₁ and θ₂ are the angles of elevation from A to the top and bottom of a vertically held rod of length S at B, the horizontal distance AB is

AS/(tanθ₁ + tanθ₂)

BS/( tanθ₂ - tanθ₁)

CS/(tanθ₁ * tanθ₂)

DS/(tanθ₁ - tanθ₂)

Answer:

D. S/(tanθ₁ - tanθ₂)


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