from the questions,
$45-9+4\times5substitutethesymbolonthreircorrespondingplaces,- changed to\div,+ changed to \times,\times changed to +.</p><pstyle="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px"data−pxy="true">ByusingBODMAS,</p><pstyle="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px"data−pxy="true">45\div9\times4+5=(\frac{45}9\times4)+5</p><pstyle="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px"data−pxy="true">=(5\times4)+5=20+5</p><pstyle="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px"data−pxy="true">=25$