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Ifx2+1/x2=38x^2+1/x^2=38then what is the value of |x-1/x|?

A5

B6

C12

D18

Answer:

B. 6

Read Explanation:

If x2+1/x2=kx^2+1/x^2=kthen, x1/x=k2x-1/x=\sqrt{k-2}

So here,

x2+1/x2=38x^2+1/x^2=38 then,

x1/x=382=36=6x-1/x=\sqrt{38-2}=\sqrt{36}=6


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