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In a circle, PM and QN intersect at a point O. If PM = 15 cm, find the length of OM.

A10 cm

B7.5 cm

C5 cm

D6 cm

Answer:

C. 5 cm

Read Explanation:

Based on the standard geometry problem (where PMPM and QNQN are medians of a triangle intersecting at the centroid OO):

The point of intersection of the medians of a triangle is the centroid, which divides each median in a 2:12:1 ratio from the vertex to the midpoint of the opposite side.


  • Here, PMPM is a median, and point OO is the centroid.

  • This means the ratio of PO ⁣:OM=2 ⁣:1PO \colon OM = 2 \colon 1.

  • Therefore, segment OMOM is 13\frac{1}{3} of the total length of the median PMPM.

Step-by-Step Calculation

Length of OM=13×Length of PM\text{Length of } OM = \frac{1}{3} \times \text{Length of } PM

Length of OM=13×15 cm=5 cm\text{Length of } OM = \frac{1}{3} \times 15\text{ cm} = 5\text{ cm}

Answer

The correct option is 5 cm (Option c).


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