Question

In a tournament of 7 players, each player plays every other player once. How many matches are there?

• A. 21
• B. 42
• C. 36
• D. 28

Answer 1

Answer:

A. 21

If each player plays every other player once, the number of matches is:

$\frac{n(n-1)}{2}$

where (n = 7).

$\frac{7 \times 6}{2} = \frac{42}{2} = 21$

Therefore, the total number of matches is:

$\boxed{21}$