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In an election, 80% of eligible voters cast their votes. Of these votes, 5% were declared invalid. If a winning candidate received 11,400 votes, which accounted for 60% of the total valid votes, what was the total number of eligible voters enrolled in that election?

A20,000

B22,500

C25,000

D27,500

Answer:

C. 25,000

Read Explanation:

Winning candidate received 11,400 votes, which is (60%) of the valid votes.

Let total valid votes be (V).

60% of V=11,40060\% \text{ of } V = 11,400
60100V=11,400\frac{60}{100}V = 11,400

V=11,400×10060=19,000V = \frac{11,400 \times 100}{60} = 19,000

So, total valid votes (= 19,000).

Since (5%) votes were invalid, valid votes are (95%) of total votes cast.

Let total votes cast be (C).

95% of C=19,00095\% \text{ of } C = 19,000
C=19,000×10095=20,000C = \frac{19,000 \times 100}{95} = 20,000

Now, (80%) of eligible voters cast votes.

Let total eligible voters be (E).

80% of E=20,00080\% \text{ of } E = 20,000
E=20,000×10080=25,000E = \frac{20,000 \times 100}{80} = 25,000

25,000\boxed{25,000}


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