In an isosceles triangle ABC, if AB = AC = 26 cm and BC = 20 cm, find the area of triangle ABC.

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ഒരു സമപാർശ്വ ത്രികോണമായ ABCയിൽ, AB = AC = 26 cm ഉം BC = 20 cm ഉം ആണെങ്കിൽ, ABC ത്രികോണത്തിന്റെ വിസ്തീർണ്ണം കണ്ടെത്തുക.

A180 cm²

B240 cm²

C220 cm²

D260 cm²

Answer:

A = b/4[√(4a² − b²)] = 20/4[√(4 × 676 − 400)] = 5 × 48 = 240

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