In any triangle ABC cos- A+B/ 2 is equal to:
ASin C/2
BCos C/2
Csin A/2
Dcos B/2
ASin C/2
BCos C/2
Csin A/2
Dcos B/2
Related Questions:
In the figure <CAB=30°, <CPB=60°. AP 10 centimeters. Area of the rectangle ABCD is.............................. square centimeters.
In the figure AB= BC=CD=DE=AE. <C=<D=90°. what is the measure of <A?